What is the voltage drop for a single-phase circuit carrying 32 amperes over a distance of 320 feet using 8 AWG copper conductors?

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Multiple Choice

What is the voltage drop for a single-phase circuit carrying 32 amperes over a distance of 320 feet using 8 AWG copper conductors?

Explanation:
To determine the voltage drop in a single-phase circuit carrying 32 amperes over a distance of 320 feet using 8 AWG copper conductors, we can use the voltage drop formula: Voltage Drop (V) = 2 x Length (feet) x Current (Amps) x Resistivity (Ohms per foot) For copper conductors, the resistivity at room temperature is approximately 0.001588 Ohms per foot for 8 AWG wire. Here’s how the calculation unfolds: 1. **Calculate the distance in one direction**: Since the circuit includes both the outgoing and return path, you double the length, which gives us 640 feet. 2. **Insert the values into the formula**: - Length = 640 feet (total round trip distance) - Current = 32 Amps - Resistivity for 8 AWG copper = 0.001588 Ohms/foot 3. **Calculate the voltage drop**: \[ Voltage Drop = 2 x 320 \text{ feet} x 32 \text{ Amps} x 0.001588 \text{ Ohms/foot} \] \[ Voltage Drop

To determine the voltage drop in a single-phase circuit carrying 32 amperes over a distance of 320 feet using 8 AWG copper conductors, we can use the voltage drop formula:

Voltage Drop (V) = 2 x Length (feet) x Current (Amps) x Resistivity (Ohms per foot)

For copper conductors, the resistivity at room temperature is approximately 0.001588 Ohms per foot for 8 AWG wire.

Here’s how the calculation unfolds:

  1. Calculate the distance in one direction: Since the circuit includes both the outgoing and return path, you double the length, which gives us 640 feet.

  2. Insert the values into the formula:

  • Length = 640 feet (total round trip distance)

  • Current = 32 Amps

  • Resistivity for 8 AWG copper = 0.001588 Ohms/foot

  1. Calculate the voltage drop:

[

Voltage Drop = 2 x 320 \text{ feet} x 32 \text{ Amps} x 0.001588 \text{ Ohms/foot}

]

[

Voltage Drop

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